local p = {}  function p.factor(frame)  number = tonumber(frame.args[1])  productSymbol = frame.args['product'] or '·'  bold = frame.args['bold'] and true  big = frame.args['big'] and true  serif = frame.args['serif'] and true  primeLink = frame.args['prime'] and true   number = math.floor(number)  if number < 2 or number > 1000000 then  return '<strong class="error">number out of range</strong>'  end   result = ""  currentNumber = number  power = 0   --First take care of 2, the only even prime number.  if currentNumber % 2 == 0 then  result = '2'  currentNumber = currentNumber / 2  power = 1  end   while currentNumber % 2 == 0 do  currentNumber = currentNumber / 2  power = power + 1  end   if power > 1 then  result = result..'<sup>'..power..'</sup>'..productSymbol..' '  elseif power == 1 then  result = result..' '..productSymbol..' '  end   --Now do all odd numbers.  prime = 3   while prime <= math.sqrt(currentNumber) do   power = 0   if currentNumber % prime == 0 then  result = result..prime  currentNumber = currentNumber / prime  power = 1  end   while currentNumber % prime == 0 do  currentNumber = currentNumber / prime  power = power + 1  end   if power > 1 then  result = result..'<sup>'..power..'</sup>'..productSymbol..' '  elseif power == 1 then  result = result..' '..productSymbol..' '  end   prime = prime + 2  end   if currentNumber ~= 1 then  result = result..currentNumber..' '..productSymbol..' '  end   if currentNumber == number and primeLink then  return '[['..'prime'..']]'  end   result = string.sub(result,1,-4)   return format(result) end  function format(num)  if bold then  num = '<b>'..num..'</b>'  end   if serif then  if big then  num = '<span class="texhtml" style="font-size:165%">'..num..'</span>'  else  num = '<span class="texhtml">'..num..'</span>'  end  elseif big then  num = '<span style="font-size:165%">'..num..'</span>'  end   return num end  return p